3/10(x)-16=9/10(x)+14

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Solution for 3/10(x)-16=9/10(x)+14 equation: 



3/10(x)-16=9/10(x)+14

We move all terms to the left:

3/10(x)-16-(9/10(x)+14)=0



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R





Domain of the equation: 10x+14)!=0

x∈R



We get rid of parentheses

3/10x-9/10x-14-16=0

We multiply all the terms by the denominator


-14*10x-16*10x+3-9=0

We add all the numbers together, and all the variables

-14*10x-16*10x-6=0

Wy multiply elements

-140x-160x-6=0

We add all the numbers together, and all the variables

-300x-6=0

We move all terms containing x to the left, all other terms to the right

-300x=6

x=6/-300

x=-1/50

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