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3/10+1/5x=1/2x
We move all terms to the left:
3/10+1/5x-(1/2x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/5x-(+1/2x)+3/10=0
We get rid of parentheses
1/5x-1/2x+3/10=0
We calculate fractions
60x^2/100x^2+20x/100x^2+(-50x)/100x^2=0
We multiply all the terms by the denominator
60x^2+20x+(-50x)=0
We get rid of parentheses
60x^2+20x-50x=0
We add all the numbers together, and all the variables
60x^2-30x=0
a = 60; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·60·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*60}=\frac{0}{120} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*60}=\frac{60}{120} =1/2 $
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