3/10+d=2/7d-53/490

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Solution for 3/10+d=2/7d-53/490 equation: 


d in (-oo:+oo)

d+3/10 = (2/7)*d-(53/490) // - (2/7)*d-(53/490)

d-((2/7)*d)+3/10+53/490 = 0

d+(-2/7)*d+3/10+53/490 = 0

5/7*d+20/49 = 0 // - 20/49

5/7*d = -20/49 // : 5/7

d = -20/49/5/7

d = -4/7

d = -4/7

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