3/10p+8=1/3p

Solution for 3/10p+8=1/3p equation:

3/10p+8=1/3p

We move all terms to the left:

3/10p+8-(1/3p)=0


Domain of the equation: 10p!=0

p!=0/10

p!=0

p∈R



Domain of the equation: 3p)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

3/10p-(+1/3p)+8=0

We get rid of parentheses

3/10p-1/3p+8=0

We calculate fractions


9p/30p^2+(-10p)/30p^2+8=0

We multiply all the terms by the denominator


9p+(-10p)+8*30p^2=0

Wy multiply elements

240p^2+9p+(-10p)=0

We get rid of parentheses

240p^2+9p-10p=0

We add all the numbers together, and all the variables

240p^2-1p=0

a = 240; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·240·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*240}=\frac{0}{480}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*240}=\frac{2}{480}
=1/240
$