3/10y+12=4/5y-3

Solution for 3/10y+12=4/5y-3 equation:

3/10y+12=4/5y-3

We move all terms to the left:

3/10y+12-(4/5y-3)=0


Domain of the equation: 10y!=0

y!=0/10

y!=0

y∈R



Domain of the equation: 5y-3)!=0

y∈R


We get rid of parentheses

3/10y-4/5y+3+12=0

We calculate fractions


15y/50y^2+(-40y)/50y^2+3+12=0

We add all the numbers together, and all the variables

15y/50y^2+(-40y)/50y^2+15=0

We multiply all the terms by the denominator


15y+(-40y)+15*50y^2=0

Wy multiply elements

750y^2+15y+(-40y)=0

We get rid of parentheses

750y^2+15y-40y=0

We add all the numbers together, and all the variables

750y^2-25y=0

a = 750; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·750·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*750}=\frac{0}{1500}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*750}=\frac{50}{1500}
=1/30
$