3/13p+6=1/4p

Solution for 3/13p+6=1/4p equation:

3/13p+6=1/4p

We move all terms to the left:

3/13p+6-(1/4p)=0


Domain of the equation: 13p!=0

p!=0/13

p!=0

p∈R



Domain of the equation: 4p)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

3/13p-(+1/4p)+6=0

We get rid of parentheses

3/13p-1/4p+6=0

We calculate fractions


12p/52p^2+(-13p)/52p^2+6=0

We multiply all the terms by the denominator


12p+(-13p)+6*52p^2=0

Wy multiply elements

312p^2+12p+(-13p)=0

We get rid of parentheses

312p^2+12p-13p=0

We add all the numbers together, and all the variables

312p^2-1p=0

a = 312; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·312·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*312}=\frac{0}{624}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*312}=\frac{2}{624}
=1/312
$