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3/13x=18x
We move all terms to the left:
3/13x-(18x)=0
Domain of the equation: 13x!=0We add all the numbers together, and all the variables
x!=0/13
x!=0
x∈R
-18x+3/13x=0
We multiply all the terms by the denominator
-18x*13x+3=0
Wy multiply elements
-234x^2+3=0
a = -234; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-234)·3
Δ = 2808
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2808}=\sqrt{36*78}=\sqrt{36}*\sqrt{78}=6\sqrt{78}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{78}}{2*-234}=\frac{0-6\sqrt{78}}{-468} =-\frac{6\sqrt{78}}{-468} =-\frac{\sqrt{78}}{-78} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{78}}{2*-234}=\frac{0+6\sqrt{78}}{-468} =\frac{6\sqrt{78}}{-468} =\frac{\sqrt{78}}{-78} $
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