3/16p+9=1/5p

Solution for 3/16p+9=1/5p equation:

3/16p+9=1/5p

We move all terms to the left:

3/16p+9-(1/5p)=0


Domain of the equation: 16p!=0

p!=0/16

p!=0

p∈R



Domain of the equation: 5p)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

3/16p-(+1/5p)+9=0

We get rid of parentheses

3/16p-1/5p+9=0

We calculate fractions


15p/80p^2+(-16p)/80p^2+9=0

We multiply all the terms by the denominator


15p+(-16p)+9*80p^2=0

Wy multiply elements

720p^2+15p+(-16p)=0

We get rid of parentheses

720p^2+15p-16p=0

We add all the numbers together, and all the variables

720p^2-1p=0

a = 720; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·720·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*720}=\frac{0}{1440}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*720}=\frac{2}{1440}
=1/720
$