3/2(1+n)=-1/2n

Solution for 3/2(1+n)=-1/2n equation:

3/2(1+n)=-1/2n

We move all terms to the left:

3/2(1+n)-(-1/2n)=0


Domain of the equation: 2(1+n)!=0

n∈R



Domain of the equation: 2n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

3/2(n+1)-(-1/2n)=0

We get rid of parentheses

3/2(n+1)+1/2n=0

We calculate fractions


6n/(4n^2+4n)+(2nn/(4n^2+4n)=0


We calculate terms in parentheses: +(2nn/(4n^2+4n), so:

2nn/(4n^2+4n

We multiply all the terms by the denominator


2nn

Back to the equation:

+(2nn)


We multiply all the terms by the denominator


6n+2nn*(4n^2+4n)=0

We multiply parentheses

8n^3+8n^2+6n=0

We do not support enpression: n^3