3/2(1+r)=2/3(2-3r)

Solution for 3/2(1+r)=2/3(2-3r) equation:

3/2(1+r)=2/3(2-3r)

We move all terms to the left:

3/2(1+r)-(2/3(2-3r))=0


Domain of the equation: 2(1+r)!=0

r∈R



Domain of the equation: 3(2-3r))!=0

r∈R


We add all the numbers together, and all the variables

3/2(r+1)-(2/3(-3r+2))=0

We calculate fractions


(9r(-)/(2(r+1)*3(-3r+2)))+(-4rr/(2(r+1)*3(-3r+2)))=0


We calculate terms in parentheses: +(9r(-)/(2(r+1)*3(-3r+2))), so:

9r(-)/(2(r+1)*3(-3r+2))

We add all the numbers together, and all the variables

9r0/(2(r+1)*3(-3r+2))

We multiply all the terms by the denominator


9r0

We add all the numbers together, and all the variables

9r

Back to the equation:

+(9r)



We calculate terms in parentheses: +(-4rr/(2(r+1)*3(-3r+2))), so:

-4rr/(2(r+1)*3(-3r+2))

We multiply all the terms by the denominator


-4rr

Back to the equation:

+(-4rr)


We get rid of parentheses

9r-4rr=0