3/2(1+r)=2/3(2-3r)

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Solution for 3/2(1+r)=2/3(2-3r) equation:



3/2(1+r)=2/3(2-3r)
We move all terms to the left:
3/2(1+r)-(2/3(2-3r))=0
Domain of the equation: 2(1+r)!=0
r∈R
Domain of the equation: 3(2-3r))!=0
r∈R
We add all the numbers together, and all the variables
3/2(r+1)-(2/3(-3r+2))=0
We calculate fractions
(9r(-)/(2(r+1)*3(-3r+2)))+(-4rr/(2(r+1)*3(-3r+2)))=0
We calculate terms in parentheses: +(9r(-)/(2(r+1)*3(-3r+2))), so:
9r(-)/(2(r+1)*3(-3r+2))
We add all the numbers together, and all the variables
9r0/(2(r+1)*3(-3r+2))
We multiply all the terms by the denominator
9r0
We add all the numbers together, and all the variables
9r
Back to the equation:
+(9r)
We calculate terms in parentheses: +(-4rr/(2(r+1)*3(-3r+2))), so:
-4rr/(2(r+1)*3(-3r+2))
We multiply all the terms by the denominator
-4rr
Back to the equation:
+(-4rr)
We get rid of parentheses
9r-4rr=0

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