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3/2(10r-4)-5r=7-1/5(5-10r)
We move all terms to the left:
3/2(10r-4)-5r-(7-1/5(5-10r))=0
Domain of the equation: 2(10r-4)!=0
r∈R
Domain of the equation: 5(5-10r))!=0We add all the numbers together, and all the variables
r∈R
3/2(10r-4)-5r-(7-1/5(-10r+5))=0
We add all the numbers together, and all the variables
-5r+3/2(10r-4)-(7-1/5(-10r+5))=0
We calculate fractions
-5r+(15r(-)/(2(10r-4)*5(-10r+5)))+(-(-2r1)/(2(10r-4)*5(-10r+5)))=0
We calculate terms in parentheses: +(15r(-)/(2(10r-4)*5(-10r+5))), so:
15r(-)/(2(10r-4)*5(-10r+5))
We add all the numbers together, and all the variables
15r0/(2(10r-4)*5(-10r+5))
We multiply all the terms by the denominator
15r0
We add all the numbers together, and all the variables
15r
Back to the equation:
+(15r)
We calculate terms in parentheses: +(-(-2r1)/(2(10r-4)*5(-10r+5))), so:We add all the numbers together, and all the variables
-(-2r1)/(2(10r-4)*5(-10r+5))
We add all the numbers together, and all the variables
-(-2r)/(2(10r-4)*5(-10r+5))
We multiply all the terms by the denominator
-(-2r)
We get rid of parentheses
2r
Back to the equation:
+(2r)
12r=0
r=0/12
r=0
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