3/2(2d+12)=1/2(2d-6)

Solution for 3/2(2d+12)=1/2(2d-6) equation:

3/2(2d+12)=1/2(2d-6)

We move all terms to the left:

3/2(2d+12)-(1/2(2d-6))=0


Domain of the equation: 2(2d+12)!=0

d∈R



Domain of the equation: 2(2d-6))!=0

d∈R


We calculate fractions


(6d2/(2(2d+12)*2(2d-6)))+(-2d2/(2(2d+12)*2(2d-6)))=0


We calculate terms in parentheses: +(6d2/(2(2d+12)*2(2d-6))), so:

6d2/(2(2d+12)*2(2d-6))

We multiply all the terms by the denominator


6d2

We add all the numbers together, and all the variables

6d^2

Back to the equation:

+(6d^2)



We calculate terms in parentheses: +(-2d2/(2(2d+12)*2(2d-6))), so:

-2d2/(2(2d+12)*2(2d-6))

We multiply all the terms by the denominator


-2d2

We add all the numbers together, and all the variables

-2d^2

Back to the equation:

+(-2d^2)


We add all the numbers together, and all the variables

6d^2+(-2d^2)=0

We get rid of parentheses

6d^2-2d^2=0

We add all the numbers together, and all the variables

4d^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{0}{8}=0$