3/2(2p-5)+4=10

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Solution for 3/2(2p-5)+4=10 equation: 



3/2(2p-5)+4=10

We move all terms to the left:

3/2(2p-5)+4-(10)=0



Domain of the equation: 2(2p-5)!=0

p∈R



We add all the numbers together, and all the variables

3/2(2p-5)-6=0

We multiply all the terms by the denominator


-6*2(2p-5)+3=0

Wy multiply elements

-12p(2+3=0

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