3/2(2x+4)=x+19

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Solution for 3/2(2x+4)=x+19 equation: 



3/2(2x+4)=x+19

We move all terms to the left:

3/2(2x+4)-(x+19)=0



Domain of the equation: 2(2x+4)!=0

x∈R



We get rid of parentheses

3/2(2x+4)-x-19=0

We multiply all the terms by the denominator


-x*2(2x+4)-19*2(2x+4)+3=0

Wy multiply elements

-2x^2(2-38x(2+3=0

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