3/2(2z+4)-z=10z-2(4z-3)

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Solution for 3/2(2z+4)-z=10z-2(4z-3) equation: 



3/2(2z+4)-z=10z-2(4z-3)

We move all terms to the left:

3/2(2z+4)-z-(10z-2(4z-3))=0



Domain of the equation: 2(2z+4)!=0

z∈R



We add all the numbers together, and all the variables

-1z+3/2(2z+4)-(10z-2(4z-3))=0

We multiply all the terms by the denominator


-1z*2(2z+4)-((10z-2(4z-3)))*2(2z+4)+3=0



We calculate terms in parentheses: -((10z-2(4z-3)))*2(2z+4), so:

(10z-2(4z-3)))*2(2z+4



Wy multiply elements

-2z^2(2-((10z-2(4z-3)))*2(2z+4)+3=0

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