3/2(3t-6)+1=5

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Solution for 3/2(3t-6)+1=5 equation: 



3/2(3t-6)+1=5

We move all terms to the left:

3/2(3t-6)+1-(5)=0



Domain of the equation: 2(3t-6)!=0

t∈R



We add all the numbers together, and all the variables

3/2(3t-6)-4=0

We multiply all the terms by the denominator


-4*2(3t-6)+3=0

Wy multiply elements

-8t(3+3=0

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