3/2(3x+1)=2(3-4x)+8

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Solution for 3/2(3x+1)=2(3-4x)+8 equation: 


x in (-oo:+oo)

(3/2)*(3*x+1) = 2*(3-(4*x))+8 // - 2*(3-(4*x))+8

(3/2)*(3*x+1)-(2*(3-(4*x)))-8 = 0

(3/2)*(3*x+1)-2*(3-4*x)-8 = 0

3/2*(3*x+1)-2*(3-4*x)-8 = 0

3/2*(3*x+1)-2*(3-4*x)-8 = 0

25/2*x-8-9/2 = 0

25/2*x-25/2 = 0

25/2*x-25/2 = 0

25/2*x-25/2 = 0 // + 25/2

25/2*x = 25/2 // : 25/2

x = 25/2/25/2

x = 1

x = 1

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