3/2(3x+3)=4(1-3x)+17

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Solution for 3/2(3x+3)=4(1-3x)+17 equation: 


x in (-oo:+oo)

(3/2)*(3*x+3) = 4*(1-(3*x))+17 // - 4*(1-(3*x))+17

(3/2)*(3*x+3)-(4*(1-(3*x)))-17 = 0

(3/2)*(3*x+3)-4*(1-3*x)-17 = 0

3/2*(3*x+3)-4*(1-3*x)-17 = 0

3/2*(3*x+3)-4*(1-3*x)-17 = 0

33/2*x-17+1/2 = 0

33/2*x-33/2 = 0

33/2*x-33/2 = 0

33/2*x-33/2 = 0 // + 33/2

33/2*x = 33/2 // : 33/2

x = 33/2/33/2

x = 1

x = 1

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