3/2(4+8x)-5=2(x+3)-10

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Solution for 3/2(4+8x)-5=2(x+3)-10 equation:



3/2(4+8x)-5=2(x+3)-10
We move all terms to the left:
3/2(4+8x)-5-(2(x+3)-10)=0
Domain of the equation: 2(4+8x)!=0
x∈R
We add all the numbers together, and all the variables
3/2(8x+4)-(2(x+3)-10)-5=0
We multiply all the terms by the denominator
-((2(x+3)-10))*2(8x+4)-5*2(8x+4)+3=0
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
Wy multiply elements
-((2(x+3)-10))*2(8x+4)-10x(8+3=0
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4
We calculate terms in parentheses: -((2(x+3)-10))*2(8x+4), so:
(2(x+3)-10))*2(8x+4

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