3/2(4x+12)=6x+18

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Solution for 3/2(4x+12)=6x+18 equation: 



3/2(4x+12)=6x+18

We move all terms to the left:

3/2(4x+12)-(6x+18)=0



Domain of the equation: 2(4x+12)!=0

x∈R



We get rid of parentheses

3/2(4x+12)-6x-18=0

We multiply all the terms by the denominator


-6x*2(4x+12)-18*2(4x+12)+3=0

Wy multiply elements

-12x^2(4-36x(4+3=0

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