3/2(4x+3)+(6x+1)=43

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Solution for 3/2(4x+3)+(6x+1)=43 equation: 



3/2(4x+3)+(6x+1)=43

We move all terms to the left:

3/2(4x+3)+(6x+1)-(43)=0



Domain of the equation: 2(4x+3)!=0

x∈R



We get rid of parentheses

3/2(4x+3)+6x+1-43=0

We multiply all the terms by the denominator


6x*2(4x+3)+1*2(4x+3)-43*2(4x+3)+3=0

Wy multiply elements

12x^2(4+2x(4-86x(4+3=0

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