3/2(4x-1)-3x=5/4-(x+2);x=1/6

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Solution for 3/2(4x-1)-3x=5/4-(x+2);x=1/6 equation: 



3/2(4x-1)-3x=5/4-(x+2)x=1/6

We move all terms to the left:

3/2(4x-1)-3x-(5/4-(x+2)x)=0



Domain of the equation: 2(4x-1)!=0

x∈R





Domain of the equation: 4-(x+2)x)!=0

We move all terms containing x to the left, all other terms to the right

-(x+2)x)!=-4

x∈R



We add all the numbers together, and all the variables

-3x+3/2(4x-1)-(5/4-(x+2)x)=0

We calculate fractions


-3x+(-(x+2)x)+3*4)/(32x-(x+2)x)-8)+(-10x4/(32x-(x+2)x)-8)=0



We calculate terms in parentheses: +(-(x+2)x), so:

-(x+2)x

We multiply parentheses

-x^2-2x

We add all the numbers together, and all the variables

-1x^2-2x

Back to the equation:

+(-1x^2-2x)



We get rid of parentheses

-1x^2-2x-3x+3*4)/(32x-(x+2)x)-8)+(-10x4/(32x-x-2)x)-8=0

We multiply all the terms by the denominator


-1x^2*(32x-2x*(32x-3x*(32x+3*4)-(x+2)x)-8)+(-10x4-x*(32x-2x)-8)*(32x=0

We add all the numbers together, and all the variables

-1x^2*(32x-2x*(32x-3x*(32x+12)-(x+2)x)-8)+(-10x4-x*(+30x)-8)*(32x=0

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