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3/2(4x-1)-3x=5/4-1(x+2)
We move all terms to the left:
3/2(4x-1)-3x-(5/4-1(x+2))=0
Domain of the equation: 2(4x-1)!=0
x∈R
Domain of the equation: 4-1(x+2))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-1(x+2))!=-4
x∈R
-3x+3/2(4x-1)-(5/4-1(x+2))=0
We calculate fractions
-3x+(-1(x+2))+3*4)/(32x-1(x+2))-8)+(-10x4/(32x-1(x+2))-8)=0
We calculate terms in parentheses: +(-1(x+2)), so:We multiply all the terms by the denominator
-1(x+2)
-3x*(32x+((-1(x+2)))*(32x+3*4)-1(x+2))-10x4-(1(x+2))-8))*(32x-8)+(=0
We calculate terms in parentheses: -(1(x+2)), so:We add all the numbers together, and all the variables
1(x+2)
-3x*(32x+((-1(x+2)))*(32x+12)-1(x+2))-10x4-(1(x+2))-8))*(32x-8)+(=0
We add all the numbers together, and all the variables
-10x^4-3x*(32x+((-1(x+2)))*(32x+12)-1(x+2))-(1(x+2))-8))*(32x-8)+(=0
We calculate terms in parentheses: -(1(x+2)), so:We do not support expression: x^4
1(x+2)
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