3/2(4x-10)+x=1/2(2x+2)

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Solution for 3/2(4x-10)+x=1/2(2x+2) equation: 



3/2(4x-10)+x=1/2(2x+2)

We move all terms to the left:

3/2(4x-10)+x-(1/2(2x+2))=0



Domain of the equation: 2(4x-10)!=0

x∈R





Domain of the equation: 2(2x+2))!=0

x∈R



We add all the numbers together, and all the variables

x+3/2(4x-10)-(1/2(2x+2))=0

We calculate fractions


x+(6x2/(2(4x-10)*2(2x+2)))+(-2x4/(2(4x-10)*2(2x+2)))=0



We calculate terms in parentheses: +(6x2/(2(4x-10)*2(2x+2))), so:

6x2/(2(4x-10)*2(2x+2))

We multiply all the terms by the denominator


6x2

We add all the numbers together, and all the variables

6x^2

Back to the equation:

+(6x^2)





We calculate terms in parentheses: +(-2x4/(2(4x-10)*2(2x+2))), so:

-2x4/(2(4x-10)*2(2x+2))

We multiply all the terms by the denominator


-2x4

We add all the numbers together, and all the variables

-2x^4

We do not support expression: x^4

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