3/2(4x-10)+x=1/2(2x+2)

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Solution for 3/2(4x-10)+x=1/2(2x+2) equation:



3/2(4x-10)+x=1/2(2x+2)
We move all terms to the left:
3/2(4x-10)+x-(1/2(2x+2))=0
Domain of the equation: 2(4x-10)!=0
x∈R
Domain of the equation: 2(2x+2))!=0
x∈R
We add all the numbers together, and all the variables
x+3/2(4x-10)-(1/2(2x+2))=0
We calculate fractions
x+(6x2/(2(4x-10)*2(2x+2)))+(-2x4/(2(4x-10)*2(2x+2)))=0
We calculate terms in parentheses: +(6x2/(2(4x-10)*2(2x+2))), so:
6x2/(2(4x-10)*2(2x+2))
We multiply all the terms by the denominator
6x2
We add all the numbers together, and all the variables
6x^2
Back to the equation:
+(6x^2)
We calculate terms in parentheses: +(-2x4/(2(4x-10)*2(2x+2))), so:
-2x4/(2(4x-10)*2(2x+2))
We multiply all the terms by the denominator
-2x4
We add all the numbers together, and all the variables
-2x^4
We do not support expression: x^4

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