3/2(4x-10)=-1/3(6x+12)+8

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Solution for 3/2(4x-10)=-1/3(6x+12)+8 equation: 


x in (-oo:+oo)

(3/2)*(4*x-10) = (-1/3)*(6*x+12)+8 // - (-1/3)*(6*x+12)+8

(3/2)*(4*x-10)-((-1/3)*(6*x+12))-8 = 0

(3/2)*(4*x-10)+(1/3)*(6*x+12)-8 = 0

3/2*(4*x-10)+1/3*(6*x+12)-8 = 0

3/2*(4*x-10)+1/3*(6*x+12)-8 = 0

8*x-11-8 = 0

8*x-19 = 0

8*x-19 = 0

8*x-19 = 0 // + 19

8*x = 19 // : 8

x = 19/8

x = 19/8

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