3/2(4x-2)=10x+7

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Solution for 3/2(4x-2)=10x+7 equation: 



3/2(4x-2)=10x+7

We move all terms to the left:

3/2(4x-2)-(10x+7)=0



Domain of the equation: 2(4x-2)!=0

x∈R



We get rid of parentheses

3/2(4x-2)-10x-7=0

We multiply all the terms by the denominator


-10x*2(4x-2)-7*2(4x-2)+3=0

Wy multiply elements

-20x^2(4-14x(4+3=0

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