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3/2(6x+1)=1/2(14x-5)
We move all terms to the left:
3/2(6x+1)-(1/2(14x-5))=0
Domain of the equation: 2(6x+1)!=0
x∈R
Domain of the equation: 2(14x-5))!=0We calculate fractions
x∈R
(6x1/(2(6x+1)*2(14x-5)))+(-2x6/(2(6x+1)*2(14x-5)))=0
We calculate terms in parentheses: +(6x1/(2(6x+1)*2(14x-5))), so:
6x1/(2(6x+1)*2(14x-5))
We multiply all the terms by the denominator
6x1
We add all the numbers together, and all the variables
6x
Back to the equation:
+(6x)
We calculate terms in parentheses: +(-2x6/(2(6x+1)*2(14x-5))), so:
-2x6/(2(6x+1)*2(14x-5))
We multiply all the terms by the denominator
-2x6
We add all the numbers together, and all the variables
-2x^6
We do not support expression: x^6
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