3/2(6x+1)=1/2(14x-5)

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Solution for 3/2(6x+1)=1/2(14x-5) equation: 



3/2(6x+1)=1/2(14x-5)

We move all terms to the left:

3/2(6x+1)-(1/2(14x-5))=0



Domain of the equation: 2(6x+1)!=0

x∈R





Domain of the equation: 2(14x-5))!=0

x∈R



We calculate fractions


(6x1/(2(6x+1)*2(14x-5)))+(-2x6/(2(6x+1)*2(14x-5)))=0



We calculate terms in parentheses: +(6x1/(2(6x+1)*2(14x-5))), so:

6x1/(2(6x+1)*2(14x-5))

We multiply all the terms by the denominator


6x1

We add all the numbers together, and all the variables

6x

Back to the equation:

+(6x)





We calculate terms in parentheses: +(-2x6/(2(6x+1)*2(14x-5))), so:

-2x6/(2(6x+1)*2(14x-5))

We multiply all the terms by the denominator


-2x6

We add all the numbers together, and all the variables

-2x^6

We do not support expression: x^6

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