3/2(6z+4)+2z=(z-6)

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Solution for 3/2(6z+4)+2z=(z-6) equation: 



3/2(6z+4)+2z=(z-6)

We move all terms to the left:

3/2(6z+4)+2z-((z-6))=0



Domain of the equation: 2(6z+4)!=0

z∈R



We add all the numbers together, and all the variables

2z+3/2(6z+4)-((z-6))=0

We multiply all the terms by the denominator


2z*2(6z+4)-(((z-6)))*2(6z+4)+3=0



We calculate terms in parentheses: -(((z-6)))*2(6z+4), so:

((z-6)))*2(6z+4



Wy multiply elements

4z^2(6-(((z-6)))*2(6z+4)+3=0

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