3/2(c-1)=1/(4c)

Solution for 3/2(c-1)=1/(4c) equation:

3/2(c-1)=1/(4c)

We move all terms to the left:

3/2(c-1)-(1/(4c))=0


Domain of the equation: 2(c-1)!=0

c∈R



Domain of the equation: 4c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

3/2(c-1)-(+1/4c)=0

We get rid of parentheses

3/2(c-1)-1/4c=0

We calculate fractions


12c/(8c^2-8c)+(-2cc/(8c^2-8c)=0


We calculate terms in parentheses: +(-2cc/(8c^2-8c), so:

-2cc/(8c^2-8c

We multiply all the terms by the denominator


-2cc

Back to the equation:

+(-2cc)


We get rid of parentheses

12c/(8c^2-8c)-2cc=0

We multiply all the terms by the denominator


12c-2cc*(8c^2-8c)=0

We multiply parentheses

-16c^3+16c^2+12c=0

We do not support ecpression: c^3