3/2(c-1)=1/2(4c)

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Solution for 3/2(c-1)=1/2(4c) equation:



3/2(c-1)=1/2(4c)
We move all terms to the left:
3/2(c-1)-(1/2(4c))=0
Domain of the equation: 2(c-1)!=0
c∈R
Domain of the equation: 24c)!=0
c!=0/1
c!=0
c∈R
We add all the numbers together, and all the variables
3/2(c-1)-(+1/24c)=0
We get rid of parentheses
3/2(c-1)-1/24c=0
We calculate fractions
72c/(48c^2-48c)+(-2cc/(48c^2-48c)=0
We calculate terms in parentheses: +(-2cc/(48c^2-48c), so:
-2cc/(48c^2-48c
We multiply all the terms by the denominator
-2cc
Back to the equation:
+(-2cc)
We get rid of parentheses
72c/(48c^2-48c)-2cc=0
We multiply all the terms by the denominator
72c-2cc*(48c^2-48c)=0
We multiply parentheses
-96c^3+96c^2+72c=0
We do not support ecpression: c^3

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