3/2(c-1)=1/2(4c)=1

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Solution for 3/2(c-1)=1/2(4c)=1 equation: 



3/2(c-1)=1/2(4c)=1

We move all terms to the left:

3/2(c-1)-(1/2(4c))=0



Domain of the equation: 2(c-1)!=0

c∈R





Domain of the equation: 24c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

3/2(c-1)-(+1/24c)=0

We get rid of parentheses

3/2(c-1)-1/24c=0

We calculate fractions


72c/(48c^2-48c)+(-2cc/(48c^2-48c)=0



We calculate terms in parentheses: +(-2cc/(48c^2-48c), so:

-2cc/(48c^2-48c

We multiply all the terms by the denominator


-2cc

Back to the equation:

+(-2cc)



We get rid of parentheses

72c/(48c^2-48c)-2cc=0

We multiply all the terms by the denominator


72c-2cc*(48c^2-48c)=0

We multiply parentheses

-96c^3+96c^2+72c=0

We do not support ecpression: c^3

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