3/2(c-2)=2/5(2c+3)

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Solution for 3/2(c-2)=2/5(2c+3) equation: 



3/2(c-2)=2/5(2c+3)

We move all terms to the left:

3/2(c-2)-(2/5(2c+3))=0



Domain of the equation: 2(c-2)!=0

c∈R





Domain of the equation: 5(2c+3))!=0

c∈R



We calculate fractions


(15c2/(2(c-2)*5(2c+3)))+(-4cc/(2(c-2)*5(2c+3)))=0



We calculate terms in parentheses: +(15c2/(2(c-2)*5(2c+3))), so:

15c2/(2(c-2)*5(2c+3))

We multiply all the terms by the denominator


15c2

We add all the numbers together, and all the variables

15c^2

Back to the equation:

+(15c^2)





We calculate terms in parentheses: +(-4cc/(2(c-2)*5(2c+3))), so:

-4cc/(2(c-2)*5(2c+3))

We multiply all the terms by the denominator


-4cc

Back to the equation:

+(-4cc)



We get rid of parentheses

15c^2-4cc=0

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