3/2(d+12)=1/2(2d*6)

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Solution for 3/2(d+12)=1/2(2d*6) equation: 



3/2(d+12)=1/2(2d*6)

We move all terms to the left:

3/2(d+12)-(1/2(2d*6))=0



Domain of the equation: 2(d+12)!=0

d∈R





Domain of the equation: 2(2d*6))!=0

d∈R



We add all the numbers together, and all the variables

3/2(d+12)-(1/2(+2d*6))=0

We calculate fractions


(36d^2(+)/(2(d+12)*2(+2d*6)))+(-2dd/(2(d+12)*2(+2d*6)))=0



We calculate terms in parentheses: +(36d^2(+)/(2(d+12)*2(+2d*6))), so:

36d^2(+)/(2(d+12)*2(+2d*6))

We add all the numbers together, and all the variables

36d^20/(2(d+12)*2(+2d*6))

We multiply all the terms by the denominator


36d^20

We do not support edpression: d^20

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