3/2(d+12)=1/2(2d-2)

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Solution for 3/2(d+12)=1/2(2d-2) equation: 



3/2(d+12)=1/2(2d-2)

We move all terms to the left:

3/2(d+12)-(1/2(2d-2))=0



Domain of the equation: 2(d+12)!=0

d∈R





Domain of the equation: 2(2d-2))!=0

d∈R



We calculate fractions


(6d2/(2(d+12)*2(2d-2)))+(-2dd/(2(d+12)*2(2d-2)))=0



We calculate terms in parentheses: +(6d2/(2(d+12)*2(2d-2))), so:

6d2/(2(d+12)*2(2d-2))

We multiply all the terms by the denominator


6d2

We add all the numbers together, and all the variables

6d^2

Back to the equation:

+(6d^2)





We calculate terms in parentheses: +(-2dd/(2(d+12)*2(2d-2))), so:

-2dd/(2(d+12)*2(2d-2))

We multiply all the terms by the denominator


-2dd

Back to the equation:

+(-2dd)



We get rid of parentheses

6d^2-2dd=0

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