3/2(d+13)=1/2(2d-6)

Solution for 3/2(d+13)=1/2(2d-6) equation:

3/2(d+13)=1/2(2d-6)

We move all terms to the left:

3/2(d+13)-(1/2(2d-6))=0


Domain of the equation: 2(d+13)!=0

d∈R



Domain of the equation: 2(2d-6))!=0

d∈R


We calculate fractions


(6d2/(2(d+13)*2(2d-6)))+(-2dd/(2(d+13)*2(2d-6)))=0


We calculate terms in parentheses: +(6d2/(2(d+13)*2(2d-6))), so:

6d2/(2(d+13)*2(2d-6))

We multiply all the terms by the denominator


6d2

We add all the numbers together, and all the variables

6d^2

Back to the equation:

+(6d^2)



We calculate terms in parentheses: +(-2dd/(2(d+13)*2(2d-6))), so:

-2dd/(2(d+13)*2(2d-6))

We multiply all the terms by the denominator


-2dd

Back to the equation:

+(-2dd)


We get rid of parentheses

6d^2-2dd=0