3/2(x+1)=1/9(x+4)

Solution for 3/2(x+1)=1/9(x+4) equation:

3/2(x+1)=1/9(x+4)

We move all terms to the left:

3/2(x+1)-(1/9(x+4))=0


Domain of the equation: 2(x+1)!=0

x∈R



Domain of the equation: 9(x+4))!=0

x∈R


We calculate fractions


(27xx/(2(x+1)*9(x+4)))+(-2xx/(2(x+1)*9(x+4)))=0


We calculate terms in parentheses: +(27xx/(2(x+1)*9(x+4))), so:

27xx/(2(x+1)*9(x+4))

We multiply all the terms by the denominator


27xx

Back to the equation:

+(27xx)



We calculate terms in parentheses: +(-2xx/(2(x+1)*9(x+4))), so:

-2xx/(2(x+1)*9(x+4))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)


We get rid of parentheses

27xx-2xx=0