3/2(x+4)+1=1/4(x+3)

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Solution for 3/2(x+4)+1=1/4(x+3) equation: 



3/2(x+4)+1=1/4(x+3)

We move all terms to the left:

3/2(x+4)+1-(1/4(x+3))=0



Domain of the equation: 2(x+4)!=0

x∈R





Domain of the equation: 4(x+3))!=0

x∈R



We calculate fractions


(12xx/(2(x+4)*4(x+3)))+(-2xx/(2(x+4)*4(x+3)))+1=0



We calculate terms in parentheses: +(12xx/(2(x+4)*4(x+3))), so:

12xx/(2(x+4)*4(x+3))

We multiply all the terms by the denominator


12xx

Back to the equation:

+(12xx)





We calculate terms in parentheses: +(-2xx/(2(x+4)*4(x+3))), so:

-2xx/(2(x+4)*4(x+3))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)



We get rid of parentheses

12xx-2xx+1=0

We move all terms containing x to the left, all other terms to the right

12xx-2xx=-1

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