3/2(x+4)=2-1/5(1-4x)

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Solution for 3/2(x+4)=2-1/5(1-4x) equation: 



3/2(x+4)=2-1/5(1-4x)

We move all terms to the left:

3/2(x+4)-(2-1/5(1-4x))=0



Domain of the equation: 2(x+4)!=0

x∈R





Domain of the equation: 5(1-4x))!=0

x∈R



We add all the numbers together, and all the variables

3/2(x+4)-(2-1/5(-4x+1))=0

We calculate fractions


(15x(-)/(2(x+4)*5(-4x+1)))+(-(-2xx)/(2(x+4)*5(-4x+1)))=0



We calculate terms in parentheses: +(15x(-)/(2(x+4)*5(-4x+1))), so:

15x(-)/(2(x+4)*5(-4x+1))

We add all the numbers together, and all the variables

15x0/(2(x+4)*5(-4x+1))

We multiply all the terms by the denominator


15x0

We add all the numbers together, and all the variables

15x

Back to the equation:

+(15x)





We calculate terms in parentheses: +(-(-2xx)/(2(x+4)*5(-4x+1))), so:

-(-2xx)/(2(x+4)*5(-4x+1))

We multiply all the terms by the denominator


-(-2xx)

We get rid of parentheses

2xx

Back to the equation:

+(2xx)

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