3/2(x+6)=16+1/2(x-24)

Solution for 3/2(x+6)=16+1/2(x-24) equation:

3/2(x+6)=16+1/2(x-24)

We move all terms to the left:

3/2(x+6)-(16+1/2(x-24))=0


Domain of the equation: 2(x+6)!=0

x∈R



Domain of the equation: 2(x-24))!=0

x∈R


We calculate fractions


(6xx/(2(x+6)*2(x-24)))+(-2xx/(2(x+6)*2(x-24)))=0


We calculate terms in parentheses: +(6xx/(2(x+6)*2(x-24))), so:

6xx/(2(x+6)*2(x-24))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)



We calculate terms in parentheses: +(-2xx/(2(x+6)*2(x-24))), so:

-2xx/(2(x+6)*2(x-24))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)


We get rid of parentheses

6xx-2xx=0