3/2(x+6)=16+1/2(x-24)

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Solution for 3/2(x+6)=16+1/2(x-24) equation:



3/2(x+6)=16+1/2(x-24)
We move all terms to the left:
3/2(x+6)-(16+1/2(x-24))=0
Domain of the equation: 2(x+6)!=0
x∈R
Domain of the equation: 2(x-24))!=0
x∈R
We calculate fractions
(6xx/(2(x+6)*2(x-24)))+(-2xx/(2(x+6)*2(x-24)))=0
We calculate terms in parentheses: +(6xx/(2(x+6)*2(x-24))), so:
6xx/(2(x+6)*2(x-24))
We multiply all the terms by the denominator
6xx
Back to the equation:
+(6xx)
We calculate terms in parentheses: +(-2xx/(2(x+6)*2(x-24))), so:
-2xx/(2(x+6)*2(x-24))
We multiply all the terms by the denominator
-2xx
Back to the equation:
+(-2xx)
We get rid of parentheses
6xx-2xx=0

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