3/2(x-5)-3/2=9/2x

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Solution for 3/2(x-5)-3/2=9/2x equation: 



3/2(x-5)-3/2=9/2x

We move all terms to the left:

3/2(x-5)-3/2-(9/2x)=0



Domain of the equation: 2(x-5)!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3/2(x-5)-(+9/2x)-3/2=0

We get rid of parentheses

3/2(x-5)-9/2x-3/2=0

We calculate fractions


6x/(2(x-5)*2x*2)+(-18xx/(2(x-5)*2x*2)=0



We calculate terms in parentheses: +(-18xx/(2(x-5)*2x*2), so:

-18xx/(2(x-5)*2x*2

We multiply all the terms by the denominator


-18xx

Back to the equation:

+(-18xx)



We get rid of parentheses

6x/(2(x-5)*2x*2)-18xx=0

We multiply all the terms by the denominator


6x-18xx*(2(x-5)*2x*2)=0

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