3/2(y-1)=y+5

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Solution for 3/2(y-1)=y+5 equation: 



3/2(y-1)=y+5

We move all terms to the left:

3/2(y-1)-(y+5)=0



Domain of the equation: 2(y-1)!=0

y∈R



We get rid of parentheses

3/2(y-1)-y-5=0

We multiply all the terms by the denominator


-y*2(y-1)-5*2(y-1)+3=0

Wy multiply elements

-2y^2(y-10y(y+3=0

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