3/2*x+4=10

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Solution for 3/2*x+4=10 equation:



3/2*x+4=10
We move all terms to the left:
3/2*x+4-(10)=0
Domain of the equation: 2*x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
3/2*x-6=0
We multiply all the terms by the denominator
-6*2*x+3=0
Wy multiply elements
-12x*x+3=0
Wy multiply elements
-12x^2+3=0
a = -12; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-12)·3
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*-12}=\frac{-12}{-24} =1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*-12}=\frac{12}{-24} =-1/2 $

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