3/2+b(b+45)(2b-90)+90=540

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Solution for 3/2+b(b+45)(2b-90)+90=540 equation: 



3/2+b(b+45)(2b-90)+90=540

We move all terms to the left:

3/2+b(b+45)(2b-90)+90-(540)=0

determiningTheFunctionDomain
b(b+45)(2b-90)+90-540+3/2=0

We add all the numbers together, and all the variables

b(b+45)(2b-90)-450+3/2=0

We multiply parentheses ..

b(+2b^2-90b+90b-4050)-450+3/2=0

We multiply all the terms by the denominator


(b(+2b^2-90b+90b-4050))*2+3-450*2=0

We add all the numbers together, and all the variables

(b(+2b^2-90b+90b-4050))*2-897=0

We move all terms containing b to the left, all other terms to the right

(b(+2b^2-90b+90b-4050))*2=897

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