3/2-(3/2)x=-3/2

Solution for 3/2-(3/2)x=-3/2 equation:

3/2-(3/2)x=-3/2

We move all terms to the left:

3/2-(3/2)x-(-3/2)=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(+3/2)x+3/2-(-3/2)=0

We multiply parentheses

-3x^2+3/2-(-3/2)=0

We get rid of parentheses

-3x^2+3/2+3/2=0

We multiply all the terms by the denominator


-3x^2*2+3+3=0

We add all the numbers together, and all the variables

-3x^2*2+6=0

Wy multiply elements

-6x^2+6=0

a = -6; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·(-6)·6
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*-6}=\frac{-12}{-12}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*-6}=\frac{12}{-12}
=-1
$