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3/24+1/6a=1/4a
We move all terms to the left:
3/24+1/6a-(1/4a)=0
Domain of the equation: 6a!=0
a!=0/6
a!=0
a∈R
Domain of the equation: 4a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
1/6a-(+1/4a)+3/24=0
We get rid of parentheses
1/6a-1/4a+3/24=0
We calculate fractions
288a^2/1152a^2+192a/1152a^2+(-288a)/1152a^2=0
We multiply all the terms by the denominator
288a^2+192a+(-288a)=0
We get rid of parentheses
288a^2+192a-288a=0
We add all the numbers together, and all the variables
288a^2-96a=0
a = 288; b = -96; c = 0;
Δ = b2-4ac
Δ = -962-4·288·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-96}{2*288}=\frac{0}{576} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+96}{2*288}=\frac{192}{576} =1/3 $
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