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3/2=(5/4)x-2x
We move all terms to the left:
3/2-((5/4)x-2x)=0
Domain of the equation: 4)x-2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-((+5/4)x-2x)+3/2=0
We calculate fractions
()/4x-2x)*2)+12x/4x-2x)*2)=0
We calculate fractions
(()*4x-2x)*2))/(16x^2-2x)*2))+(-2x)*2)+12x*4x)/(16x^2-2x)*2))=0
We calculate terms in parentheses: +(()*4x-2x)*2))/(16x^2-2x)*2))+(-2x)*2)+12x*4x)/(16x^2-2x)*2)), so:
()*4x-2x)*2))/(16x^2-2x)*2))+(-2x)*2)+12x*4x)/(16x^2-2x)*2)
We can not solve this equation
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