3/2b(b+45)+(2b-90)=90

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Solution for 3/2b(b+45)+(2b-90)=90 equation: 



3/2b(b+45)+(2b-90)=90

We move all terms to the left:

3/2b(b+45)+(2b-90)-(90)=0



Domain of the equation: 2b(b+45)!=0

b∈R



We get rid of parentheses

3/2b(b+45)+2b-90-90=0

We multiply all the terms by the denominator


2b*2b(b+45)-90*2b(b+45)-90*2b(b+45)+3=0

Wy multiply elements

4b^2(b-180b(b-180b(b+3=0

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