3/2b+19=35

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Solution for 3/2b+19=35 equation: 



3/2b+19=35

We move all terms to the left:

3/2b+19-(35)=0



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



We add all the numbers together, and all the variables

3/2b-16=0

We multiply all the terms by the denominator


-16*2b+3=0

Wy multiply elements

-32b+3=0

We move all terms containing b to the left, all other terms to the right

-32b=-3

b=-3/-32

b=3/32

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