3/2b+b(2b-90)+(b+45)+90=540

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Solution for 3/2b+b(2b-90)+(b+45)+90=540 equation: 



3/2b+b(2b-90)+(b+45)+90=540

We move all terms to the left:

3/2b+b(2b-90)+(b+45)+90-(540)=0



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



We add all the numbers together, and all the variables

3/2b+b(2b-90)+(b+45)-450=0

We multiply parentheses

2b^2+3/2b-90b+(b+45)-450=0

We get rid of parentheses

2b^2+3/2b-90b+b+45-450=0

We multiply all the terms by the denominator


2b^2*2b-90b*2b+b*2b+45*2b-450*2b+3=0

Wy multiply elements

4b^3-180b^2+2b^2+90b-900b+3=0

We do not support ebpression: b^3

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