3/2b+b(b+45)+(2b-90)+90=540

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Solution for 3/2b+b(b+45)+(2b-90)+90=540 equation: 



3/2b+b(b+45)+(2b-90)+90=540

We move all terms to the left:

3/2b+b(b+45)+(2b-90)+90-(540)=0



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



We add all the numbers together, and all the variables

3/2b+b(b+45)+(2b-90)-450=0

We multiply parentheses

b^2+3/2b+45b+(2b-90)-450=0

We get rid of parentheses

b^2+3/2b+45b+2b-90-450=0

We multiply all the terms by the denominator


b^2*2b+45b*2b+2b*2b-90*2b-450*2b+3=0

Wy multiply elements

2b^3+90b^2+4b^2-180b-900b+3=0

We do not support ebpression: b^3

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